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Mathematics 6 Online
OpenStudy (matlee):

Complicated Algebra help!

OpenStudy (matlee):

OpenStudy (reemii):

The average of some functoin \(g\) on the interval \([a,b]\) is computed by \[ \int_a^b g(x)\,dx.\] What is the rate of change of the function \(f\) at point \(x\)?

OpenStudy (reemii):

* oops * \[ \frac{1}{b-a}\int_a^b g(x)dx \] is correct

OpenStudy (matlee):

!!!

OpenStudy (reemii):

What do you mean?

OpenStudy (matlee):

I honestly have never seen this

OpenStudy (matlee):

but it is extra credit v.v

OpenStudy (reemii):

`rate of change of f(x)` is another word for `variation of f(x)` -> they're talking about the derivative of \(f\). Can you write down exactly what you have to compute?

OpenStudy (matlee):

Thats all the question says you want me to write it in here?

OpenStudy (reemii):

Nope, I let you find it yourself.

OpenStudy (reemii):

The answer is a number.

OpenStudy (matlee):

\[ f(x)=-x^2+3x+1 from x =2 \to x=5 \]

OpenStudy (matlee):

Ok just one number?

OpenStudy (reemii):

You have to compute the `average rate of change of f(x) from 2 to 5` : \[ \int_2^5 f'(x)\,dx \]

OpenStudy (reemii):

* oops * \[ \frac1{5-2}\int_2^5 f'(x)\,dx \]

OpenStudy (reemii):

You can compute the integral, either by differentiating first then integrating... or not differentiating at all. Since the antiderivative of the derivative is \(f\) itself.

OpenStudy (matlee):

I think i got it

OpenStudy (reemii):

-4 ?

OpenStudy (matlee):

Yes, i dont know what this is so i had to use a calculator

OpenStudy (reemii):

\[ \int_2^5 f'(x)\,dx = f(5) - f(2) = (-9) - 3 = -12 \] -> without computing \(f'\). then divide by 3.

OpenStudy (matlee):

Thank you

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