Complicated Algebra help!
The average of some functoin \(g\) on the interval \([a,b]\) is computed by \[ \int_a^b g(x)\,dx.\] What is the rate of change of the function \(f\) at point \(x\)?
* oops * \[ \frac{1}{b-a}\int_a^b g(x)dx \] is correct
!!!
What do you mean?
I honestly have never seen this
but it is extra credit v.v
`rate of change of f(x)` is another word for `variation of f(x)` -> they're talking about the derivative of \(f\). Can you write down exactly what you have to compute?
Thats all the question says you want me to write it in here?
Nope, I let you find it yourself.
The answer is a number.
\[ f(x)=-x^2+3x+1 from x =2 \to x=5 \]
Ok just one number?
You have to compute the `average rate of change of f(x) from 2 to 5` : \[ \int_2^5 f'(x)\,dx \]
* oops * \[ \frac1{5-2}\int_2^5 f'(x)\,dx \]
You can compute the integral, either by differentiating first then integrating... or not differentiating at all. Since the antiderivative of the derivative is \(f\) itself.
I think i got it
-4 ?
Yes, i dont know what this is so i had to use a calculator
\[ \int_2^5 f'(x)\,dx = f(5) - f(2) = (-9) - 3 = -12 \] -> without computing \(f'\). then divide by 3.
Thank you
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