Question

Please help! Will FAN AND MEDAL!
Find the x-coordinate where the graph of the function f(x) = e(–sinx) has a slope of 0.

a. pie
b. pie/4
c. pie/2
d. none of these

Answer 1

can you help @mathmale

Answer 2

Hello! Would you mind explaining your " f(x) = e(–sinx) " in words? Is that -sin x meant to be an exponent/power of the base e?

If so, please use ^ for exponentiation.

Answer 3

If you've done some calculus, well that's the approach I see

I'm wondering if we could just take the derivative of this and then set it equal to zero.

\[\frac{ d }{ dx }e^{-sinx} = e^{u}*\frac{ du }{ dx } = e^{-sinx}*\-cos(x) |_{0} \]

since we have a product of 2 functions we don't need to guess very much

\[\frac{ d }{ dx } e^{-sin(x)}*-Cos(x)\]

Answer 4

I think you could also plot this graph on wolfram alpha and look for the point where the slope is zero.

Answer 5

Personally I'd rather that aryana find the x-value at which the graph of the given function has a horiz. tan. line (that is, a line with slope 0. wolframalpha would then make for a nice means of checking your answer.

So support the idea of finding the derivative of the given function, setting it = 0, and solving for x. Aryana?

Answer 6

that's interesting, yeah it's been a while for me if there is a simpler way to do it then it's better to just use that way.

Answer 7

Aryana: check and double-check that you have correct the derivative of the given function. Then set the deriv. = to 0 and solve for x.

Answer 8

I need to get off the 'Net. Good luck!