A horse trainer is standing at the edge of a circular watching a horse and rider gallop counter clockwise around the perimeter of the track. Given that the track is 120 feet in diameter. How fast is the distance s between the trainer and the horse increasing 2pi seconds after the horse passes the trainer, if the horse is galloping at a speed of 20feet/second Please, help
|dw:1460579861644:dw|
@jhonyy9
do you have any idea for it ?
I think the angle is from 0 to 2pi, and the distance between the horse and the trainer is from 0 to 120
the speed of horse is 20 feet/sec. and the diameter is 120 feet yes right yes the distance from zero to 120 increasing and vice-versa yes ?
But I don't get what "the distance increasing 2pi seconds" mean
hope you know that pi/2 =90 degree yes ? so than pi = 180 degree so 2pi mean 360 degree what is the circumference angle of a circle yes ?
yes, then?
but it is "2pi seconds"
how it is used in this case?
oh, is it : the circumference of the circle is 120pi. and the horse gallops at 20ft/second. Hence it needs 6pi seconds to finish one cycle. Hence at 2pi seconds. it is finish 1/3 of the circumference
|dw:1460581795390:dw| use the law of cosines \(s^2 = r^2 + r^2 - 2 r r \cos \omega t\) etc \(\omega = \dfrac{v}{r}\)
That is at the point of 120 degree. and we find the distance between it with the trainer. Am I right? |dw:1460581864872:dw|
oh, yes. Thanks @IrishBoy123
mp!
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