Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Please help. I know what Im supposed to do but Im unsure how to go about solving for the initial position

OpenStudy (anonymous):

http://prntscr.com/ary7a4

OpenStudy (phi):

initial means at t=0 so put in t=0 to solve for the constant

OpenStudy (anonymous):

oh that was what i was thinking but seemed too simple

OpenStudy (anonymous):

so for the velocity vector for x the constant would be 0?

OpenStudy (anonymous):

thank you so much :)

OpenStudy (phi):

yes. then you integrate again and use t=0 , x=3 for the initial conditions on the position vector

OpenStudy (anonymous):

thank you :)

OpenStudy (anonymous):

i got t^3+3 for position for x

OpenStudy (anonymous):

and just t^2 for y

OpenStudy (phi):

yes

OpenStudy (anonymous):

thank you

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!