Question

What are the zeros of the polynomial equation
f(x)=x^2+4x-60

Answer 1

factorise it....

Answer 2

LET f(x) =0

x^2+4x-60 =0
x^2 +10x -6x -60=0 [ splitting the middle term]

can u find remaining part

Answer 3

Why did you split the middle term?

Answer 4

to get common factors

Answer 5

@SF_R http://www.purplemath.com/modules/factquad.htm

Answer 6

They are no common factors

Answer 7

Do I use the Quadratic method?

Answer 8

x is common in first two terms
and
-6 is common in next two terms

Answer 9

I am pretty sure they have to be common in all terms

Answer 10

yes ,of course u can
shall i complete this before that

Answer 11

I have the answer choices
A. -10,6
B.-14, 5
C. -6, 10
D. -5,14

Answer 12

\[x ^{2}+10x-6x-60=0\]

x*x +10x - 6x - 6*10 =0

x(x+10) -6(x+10) =0

(x+10) (x-6) =0

x+10 =0 or x-6 =0
now can u find x

Answer 13

u go through the solution

Answer 14

now you minus 10 and 0
and same for the other side but we are going to add

Answer 15

yes, write the answer

Answer 16

-10, 6

Answer 17

exactly,

Answer 18

do u understand

Answer 19

Yes! Thank you so much! :)