Why is the synthesis of isopropanol alcohol carried out at higher temperatures if the reaction is product favored at lower temperatures?
This really makes no sense to me, through calculations i found that the reaction is product favored at lower temperatures, but according to my text book, the synthesis is carried out at around 180 Celsius.
The reaction becomes reactant favored at 335.849K
Maybe the reaction happens faster at higher temperatures, but the alcohol is extracted before the reverse process can happen?
Here is the data that I am working with
I can't remember off the top of my head but I believe it has something to do with Kinetics? Like you mentioned it might be a time favored thing rather than whats appropriate for temperature.
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