Question

Please help!

A model rocket is launched from a roof into a large field. The path of the rocket can be modeled by the equation y=-0.04x^2*8.3x+4.3, where X is the horizontal distance in meters from the starting point on the roof and Y is the height in meters of the rocket above the ground. How far horizontally from its starting point will the rocket land? Round your answer to the nearest hundredth meter.

Answer 1

they're asking you to solve for x when y = 0.
Do you know the quadratic formula?
Also, there appears to be a mistake in your equation. There should be either a + or - in front of 8.3x.

Answer 2

Sorry the equation is y=-0.04x^2+8.3x+4.3

Answer 3

The quadratic formula seems to be the easiest way to do this. Have you used this before?
\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

Answer 4

Yes

Answer 5

ok, so do you know what to plug in for a, b, and c?

Answer 6

A =0.04
B =8.3
C =4.3
?

Answer 7

b and c are right.
a = -0.04

then plug & chug

Answer 8

Thank you

Answer 9

you're welcome

Answer 10

So is the answer 208.02m?

Answer 11

yes