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Chemistry 10 Online
OpenStudy (weirdjanel):

For an endothermic reaction at equilibrium, what will happen if the temperature is increased? There will be a shift toward the reactants and Keq will increase. There will be a shift toward the reactants and Keq will decrease. There will not be a shift and Keq will remain the same. There will be a shift toward the products and Keq will decrease. There will be a shift toward the products and Keq will increase.

OpenStudy (weirdjanel):

@sleepyjess

OpenStudy (weirdjanel):

@jabez177

jabez177 (jabez177):

I can't think right now. I just got up. Sorry! :(

OpenStudy (weirdjanel):

@jabez177 You're good lmao

OpenStudy (weirdjanel):

@mathstudent55

OpenStudy (jfraser):

if the reaction is endothermic, where does the heat energy belong, as a reactant, or a product?

OpenStudy (weirdjanel):

@Ciarán95 You good? lmao

OpenStudy (weirdjanel):

@JFraser As a reactant.

OpenStudy (weirdjanel):

I need a straight up answer to this question.

OpenStudy (ciarán95):

This has all got to do with Le Chatelier's Principle, which tells us how a system in equilibrium will react to any changes made to it (in temperature, concentrations or pressure). An endothermic reaction is one where, in going from the reactants to the products, energy needs to be abosrbed (e.g. in the form of heat). So, the deltaH (the enthalpy) for this kind of reaction would be a positive value, as we would have to input energy to create the products. For this reaction, we'll assume that the forward reaction is the endothermic reaction, where A and B are our reactants and C and D are our products. \[A + B \leftarrow \rightarrow C + D~(DeltaH=+)\] Le Chatelier's Principle states that for a reaction in a dynamic equilibrium, if the system undergoes a change the equilibrium will shift in order to counteract that change. So, if we had an equilibrium system and we were to heat it up, the system will try to respond by getting rid of this excess heat. How does it do this? Well, it will shift the equilibrium such that the endothermic reaction is favoured, in doing so using up this excess heat. In our case, that means the forward reaction will be favoured and we will get more of our products (C and D). Keq, the equilibrium constant, is a measure of how much the forward or backward reaction are favoured over one another when the system is at equilibrium. It is expressed in terms of the concentrations of the products and reactants at equilibrium. \[K _{eq} = \frac{ [C][D] }{ [A][B] }\] So, if the endothermic reaction is now favoured and we are producing more of C and D, then the value of Keq will get bigger. Hope that helps! :)

OpenStudy (hannahgrace4464):

please help me on my question! ^-^

OpenStudy (weirdjanel):

Bruh everyone needs to chill lmao. @Ciarán95 Thank you haha, for going through all that trouble to write that.

OpenStudy (ciarán95):

No worries @weirdjanel ! Hopefully you're able to understand the answer. If you have any questions about it though let me know :D

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