Question

help plz
Convert the rectangular equation to a polar equation that expresses r in terms of thetaθ.

Answer 1

x^2 + (y-8)^2 = 64

Answer 2

Ooo ok ok ok ok ok
I got it.

Answer 3

\[\large\rm x^2+(y-8)^2=64\]So recall that you use these two equations to make your conversion to polar,\[\large\rm x=r \cos \theta\qquad\qquad\qquad y=r \sin \theta\]So let's plug those in and see what happens,\[\large\rm (r \cos \theta)^2+(r \sin \theta-8)^2=64\]

Answer 4

We replaced our `x with rcos(theta)` and `y with rsin(theta)`.
Distribute the square in the first term.
\[\large\rm r^2\cos^2\theta+(r \sin \theta-8)^2=64\]Do you understand how to expand out the other square?

Answer 5

nope not really