Question

Can someone please see if I'm doing this wrong? Then problem is below

Answer 1

Notice that the figure has already been labeled. The variable x is used to represent the unknown width of the path.
The are of a pool and the path combined is 748 square meters
Notice that the length of the combined area is 22+2x and the width combined are is 10+2x

Answer 2

recall that the formula for the area of a rectangle is area=length*width
we use the figure and the information given to write an equation for the area of the pool and path combined
\[(10+2x)(22+2x)\]

Answer 3

I mean \[(10+2x)(22+2x)=748\]

Answer 4

That's right, solve for x now which is the width of the path

Answer 5

Solve the equation. The solutions to the equation are the values of x that satisfy the condition given in the problem
I rewrite the problem into a standard form
\[4x2+220+?=748\]

Answer 6

I don't know what the third term would be

Answer 7

(10+2x)(22+2x)=748

\(220+20x+44x+4x^2=748\)

\(220+64x +4x^2=748\)

\(220-748+64x +4x^2=0 \)

\( -528+64x +4x^2=0 \)

Answer 8

Then move all terms to the left side of the equation, obtaining zero on the right side
which you already give thank you

Answer 9

Now that the quadratic equation is in standard form, factor the quadratic completely. First factor out the greatest common factor (GCF), the factor the trinomial

Answer 10

yup, divide all by 4

-132 + 16x + x^2 =0

Answer 11

now you need two numbers that add up to +16 but multiply to -132

Answer 12

22 and 6 maybe?

Answer 13

Yes, thank you