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Geometry 8 Online
OpenStudy (tylermckinney16):

I need help please!!!!

OpenStudy (tylermckinney16):

Questions here.

OpenStudy (igigighjkl):

@mathmale he needs your help

OpenStudy (tylermckinney16):

@welshfella

OpenStudy (welshfella):

triangle ABC is isosceles because AB = AC ( 2 radii) Therefore CE = BE ( because triangle ABC is isosceles and AE is perpendicular to BC.)

OpenStudy (tylermckinney16):

Ok

OpenStudy (welshfella):

I guess you need a 2 column proof but im not too good at those. I never learned that in the UK.

OpenStudy (welshfella):

If you join C to D and B to D . the triangle CDB becomes isosceles because ED is the perpendicular bisector of CB. Therefore CD = BD.

OpenStudy (tylermckinney16):

So is that the first answer?

OpenStudy (welshfella):

No thats the last One we've done the 2 parts.

OpenStudy (tylermckinney16):

So they both are the answers?

OpenStudy (welshfella):

we've proved that BE = CE and also CD = BD.

OpenStudy (welshfella):

Algebra in UK and US are very similar, Geometry is not.

OpenStudy (tylermckinney16):

Oh ok.

OpenStudy (tylermckinney16):

AC= AB = radius = R AE is shared by triangles: ACE and ABE, Angle AEC = Angle AEB = 90 degrees Therefore, ACE and ABE are congruent via SAS rule. (Side, Angle, Side) Therefore CE and EB ; Sides of triangles ACE and ABE respectively, are the same -- Angles CAE and BAE are the same as triangles ACE and ABE are congruent. Assume angles CAE/BAE = x The arc length of a fraction of a circle = radius * x, where x is the angle in radians CD = x*radius BD = x*radius Therefore CD and BD are equal.

OpenStudy (tylermckinney16):

Is this somewhat right?

OpenStudy (welshfella):

In US geometry there are different labels for postulates and theorems.

OpenStudy (welshfella):

Yes - except the reasons will probably have different labels.

OpenStudy (tylermckinney16):

Ok so i just put what i did?

OpenStudy (welshfella):

well I would try and put it into a 2 column proof

OpenStudy (welshfella):

I'm sure you'll get some credit for it.

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