Could someone help me out? Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular snow cone that has a spherical piece of bubble gum nested at the bottom of the cone. The radius of the snow cone is 4 inches, and the height of the cone is 6 inches. If the diameter of the bubble gum is 0.8 inches, which of the following can be used to calculate the volume of the cone that can be filled with flavored ice? 1 over 3(3.14)(6^2)(4) − 4 over 3(3.14)(0.43^3) 1 over 3(3.14)(4^2)(6) − 4 over 3(3.14)(0.43^3) 1 over 3(3.14)(6^2)(4) − 4 over 3(3.14)(0.83^3) 1 over 3(3.14)(4^2)(6) − 4 over 3(3.14)(0.8
The last answer cut off (0.83^3)
@clanger555 could you help?
@Aveline
that would be the volume of the cone minus the volume of the bubble gum
How would i find the volume
V=πr2h 3
volume of a cone is \[(1/3) \pi r ^{2}h\]
1/3 =3.14 4^2 6 is that right?
Yes that's the volume of the cone where r=4 and h=6
Volume of a sphere is ... \[(4/3)\pi r ^{3}\]
for the bubble gum it is only giving diameter
Radius is half of Diameter
well the diameter is just twice the radius
oh yeah.. i forgot lol
So now you should be able to pick the correct answer
so 4/3 (3.14) .4^3
so B? @alekos
@alekos is B right?
Yes. but I don't know where the 0.43 came from , probably a typo
Yeah it is sorry. Thank you so much!
no worries
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