4) How many solutions does each equation have a) 4y – 4y – 12 = 14 – 2 b) –3y + 3y + 4 = 4 c) 3x + 6 = –1 – 3 + 4x
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http://www.shmoop.com/equations-inequalities/equations-many-solutions.html
Heeelp
Go to that link?
A.) and B.) are going to be the same. What do you notice about the Y values?
What do you mean? I see there are 2 in both equations with the same numbers.
That's a good start Are the both positive, negative, or one of each?
One of each
Right, so for the first one \[4y-4y=?\]
Wait, I dont understand what you're asking for
Just a subtraction problem If you had "4y" of something and I took away "4y" of something from you, how much would you have
0
just the y or would that be gone too?
Right, it would be gone too because it works the same way as just numbers. If it helps, you could forget about the y 4-4 = 0 Then add the y back on 0y, which is 0 basically
Ok
Next step?
Which means the y is gone, leaving us with \[-12=14-2\] (Sorry, Im having some script problems so I'm lagging)
If that statement true or false
So no solution1
Correct
And since the 2nd equation is the same it will be no solution for that one too!
Not exactly the same, but it is the same to an extent of the y's -3y + 3y is saying -3+3=? That is 0, so that leaves us with 4=4 That's true or false?
Not understanding what you're asking again.
I am back from work Part B: \[–3y + 3y + 4 = 4 \] When we subtracted 3y-3y, we got 0, giving us \[4 = 4\] This means the line of y = 4 is on top of the line of y = 4, so for whatever value X we look at, the y value for both lines will always be the same... which would be 4. That means we have an infinite number of solutions.
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