Question

The function is continuous on the interval [10, 20] with some of its values given in the table above. Estimate the average value of the function with a Right Hand Sum Approximation, using the intervals between those given points.

Answer 1

@phi

Answer 2

@Loser66

Answer 3

@freckles

Answer 4

you are starting calculus ?

Do you know how to do this and want your answer checked ?

Answer 5

oh sorry that's not my answer I just couldn't un-click the option

Answer 6

i'm in my second semester of Calc

Answer 7

you make "rectangles" with sides at the x values
the y value is the value on the "right" i.e. the bigger x value
for example the first rectangle goes from
10 to 12 (width 2)
height of y= -5 (the value of the function at x=12)
the area is 2*-5 = -10

do that for the next pair x=12 to 15

Answer 8

x=12 to 15 (width 5)
height of y= -9
area is 5*-9 = -45

Answer 9

12 to 15 is width 3 (15-12)

Answer 10

oh then 3*-9 = -27

Answer 11

yes

now do 15 to 19

Answer 12

4*-12= -48

Answer 13

and one more 19 to 20

Answer 14

5*-16= -80

Answer 15

not 5 x=19 to 20

Answer 16

the width of the last triangle is only 1 wide

Answer 17

*rectangle

Answer 18

oh I see now 1*-16 = -16

Answer 19

now add up the areas of each of those four rectangles

Answer 20

you should have -10-27-48-16

Answer 21

-101

Answer 22

the width of the region [10,20] is 20-10 = 10
we want an area of the same width but of "average" height that gives the same area -101

10 y = -101
y = -10.1

that is the "average" height of the region

Answer 23

oh wow thank you!

Answer 24

yw