Would someone please see if I'm doing this right? A pool measuring 14 by 16 meters is surrounded by a path of uniform width, as shown in the figure below. If the area of the pool and the path combined is 440 square meters, what us the width of the path
Notice that the figure has already been labeled. The variable x is used to represent the unknown width of a path. The area of a pool and a path combined is 440 square meters. Notice that the length of the combined area is 16+2x and the width of the combined area is 14+2x
Use the figure above and the information given to write an equation for an area of the pool and path combined \[(14+2x)(16+2x)=440\] Solve the equation. The solutions to this equation are the values of x that satisfy the condition given in the problem
Being by rewriting the equation is standard form \[(2x+14)(2x+16)=4x^2+32x_28x+224=440\]
I meant \[4x^2+32x+28x+224=440\] Which should end up looking like \[4x^2+60x+224=440\]
If you didn't make any arithmetic errors, then you're right.
Hang on, wouldn't the shape around the path be a rectangle?
yes
Never mind, you are absolutely right. I was thinking perimeter there for a few minutes.
Okay my computers acting up so I have to get off but I will get back now thank you @Isaiah.Feynman for your help
No probs!
Now that I got \[4x^2+60x+224=440\] Subtract 440 from each side to get \[4x^2+60x-216-440=0\]
Then I got \[4x^2+60x-656 \] divide it all by 4 \[x^2+15x+164\]
I don't know what to numbers would add up to 15 but multiply to 164
@mathmale
@agent0smith See this is how I got my answer
@Mahoganie.Carson this is how I got my answer maybe i add something wrong here?
Do it again. You made mistakes.
Do you know where?
@Atrineas
Where did I mess up Mathew?
You randomly changed positives to negatives and did some things that made no sense.
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