Question

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Answer 1

\(Al(SO_4)_3 + BaCl_2 --> AlCl_3 + BaSO_4\)

Answer 2

Reactants
Al - 2
SO4 - 3
Ba - 1
Cl - 2

Products
Al - 1
SO4 - 1
Ba - 1
Cl - 3

Answer 3

\(Al_2(SO_4)_3 + BaCl_2 -> AlCl_3 + 3Ba(SO_4)\)

Answer 4

Reactants
Al - 2
SO4 - 3
Ba - 1
Cl - 2

Products
Al - 1
SO4 - 3
Ba - 3
Cl - 3

Answer 5

\(Al_2(SO_4)_3 + 3BaCl_2 -> AlCl_3 + 3Ba(SO_4)\)
Reactants
Al - 2
SO4 - 3
Ba - 3
Cl - 6

Products
Al - 1
SO4 - 3
Ba - 3
Cl - 3

Answer 6

\(Al_2(SO_4)_3 + 3BaCl_2 -> 2AlCl_3 + 3Ba(SO_4)\)
Reactants
Al - 2
SO4 - 3
Ba - 3
Cl - 6

Products
Al - 2
SO4 - 3
Ba - 3
Cl - 6

Answer 7

@Abhisar , could you see if I did this right pwease? :)

Answer 8

\(\huge \checkmark\)

Answer 9

yayz, thank chu <3

Answer 10

Welcome c:

Answer 11

Okay, having extreme issues on this one for some reason... \(NO + O_2 -> NO_2\)

Answer 12

2NO + O2 -> 2NO2?

Answer 13

Yea, that's correct :)

Answer 14

not sure why I was having issues with that...

Answer 15

I feel dumb lol

Answer 16

no need to :P

Answer 17

\(K_2CO_3\\CaSO_4\\KNO_3\\C_8H_10N_4O_2\)

Answer 18

K- 39.1
C - 12.01
O - 16.00
Ca - 40.08
S - 32.06
N - 14.01
H- 1.01

Answer 19

For this NO + O2 -> NO2, you can also write NO + (1/2)O2 -> NO2