A ball is thrown from a height of 255 feet with an initial downward velocity of 21/fts. The ball's height h (in feet) after t seconds is given by the following.
h=255-21t-16t^2
How long after the ball is thrown does it hit the ground?
Round your answer(s) to the nearest hundredth.
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Vocaloid (vocaloid):
first step:
if the general form of a parabola is
ax^2 + bx + c
and your equation is
255-21t-16t^2
what are your a, b, and c values?
OpenStudy (anonymous):
a=16 b=21 and c=225
Vocaloid (vocaloid):
check your signs
OpenStudy (anonymous):
explain?
Vocaloid (vocaloid):
don't forget to include negative signs if they are present
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OpenStudy (anonymous):
So a=-16 b=-21 and c=225 ?
Vocaloid (vocaloid):
good!
now, are you familiar with the quadratic formula?
OpenStudy (anonymous):
|dw:1460858356802:dw|
Wouldnt this be it?
OpenStudy (anonymous):
yes that is it
Vocaloid (vocaloid):
yeah, then you just plug everything into the formula
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Vocaloid (vocaloid):
Vocaloid (vocaloid):
now, which solution do you think we should pick?
OpenStudy (anonymous):
you cant have negative time
OpenStudy (anonymous):
It would be the second option.
OpenStudy (anonymous):
yes correct
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