Question

http://prntscr.com/at7q52

Answer 1

@ganeshie8 @Miracrown @Astrophysics help pls

Answer 2

@ILovePuppiesLol http://www.purplemath.com/modules/factquad.htm

Answer 3

u need to find factor of 30 and their sum should be b ....

Answer 4

I mean u need to find b ..... get the factors

Answer 5

It says to determine two different values of “b” in \[x^2 + bx + 30\]so that the expression can be factored into the product of two binomials.

What you want, is to open two sets of parenthesis, so that x is in the first position, and since the constant is\[30\]you could have \[(+3)(+10)\]then you would have (\[x + 3)(x+10) = x^2 + 13x + 30\]so \[b = 13\]in this case.
Or, you can have \[(x + 6)(x + 5)\]which also yields \[x^ + bx + 30\]And specifically, you would have \[x^2 + 11x + 30\]so \[b = 11\]in this case. Other possibilities are possible. So 2 possible values for b is \[b = 10\]and \[b = 11\]

It says to explain how the process would change if the expression was 2x^2+bx+30

You would have to multiply 30 and 2 and get 60. Then you would have to determine the possibility of b from the factors of 60, instead of 30.

Answer 6

woah

Answer 7

so many letters and numbers ;~;

Answer 8

read it one at a time

Answer 9

yes i kinda get it now

Answer 10

i read it backwards

Answer 11

its easier starting from bottom up

Answer 12

haha well im glad you get it :)

Answer 13

thank u <3