Question

Write the standard equation for the circle that passes through the points:
(1, 7)
(8, 6)
(7, -1)


x^2+y^2 ____ x ____ y =0

Answer 1

\[x^2 + y^2+ Ax +By +C=0\]
plug in those points and find A,B,C

Answer 2

or if you prefer,
use
\[(x-h)^2 + (y-k)^2 = r^2\]
and find h,k,r by plugging in those points

Answer 3

what goes in the spots?

Answer 4

@baru

Answer 5

(x+?)+(y-?)=?

what numbers would I use from the given ones?

Answer 6

you have to substitute for x and y
for example (1,7) is a point on the circle
so substitute x=1 and y=7
and write down what you get.

do this for each of the three points

Answer 7

(1-7)^2=36
(8-6)^2=4
(7--1)^2=64

Answer 8

\[x^2 + y^2+ Ax +By +C=0\]

substitute x=1 and y=7

we get
\[1 + 49 +A + 7B +C=0\]

which simplifies to
\[A +7B +C +50 =0\]

Answer 9

you have to do the same procedure with the other two points,
and get two more equations in A,B,C

Answer 10

okay