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eliminate parameter.
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\[x=\frac{ 1 }{ 2 }t+4\]
\[y=t ^{3}\]
Plug it in! \[t=\sqrt[3]{y}\] \[x=\frac{ 1 }{ 2 }\sqrt[3]{y}+4\]
2(x-4)=t
i plugged that into my y equation.
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You can eliminate the parameter by solving for y in terms of t OR x in terms of t, then back-substitution.
would it be wrong if i did because ive been solving for x
Nah, solving for x is still a way, so you can!
Also, uh, your mathematics is right.. @FaiqRaees what was the problem?
so really one can solve for both x and y right?
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yeah!
Since you have x in terms of t and y in terms of t you can eliminate that parameter t
ty
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