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Mathematics 8 Online
OpenStudy (anonymous):

Find the limit of the function algebraically. limit as x->-3 of (x^2-9)/(x^3+3)

jimthompson5910 (jim_thompson5910):

See what happens when you do direct substitution. Replace every copy of x in `(x^2-9)/(x^3+3)` with -3 and then simplify. What do you get?

OpenStudy (anonymous):

0/-27

OpenStudy (anonymous):

it says algebraically tho

jimthompson5910 (jim_thompson5910):

Which turns into 0. So the final answer is 0.

jimthompson5910 (jim_thompson5910):

yes that was done algebraically. There's nothing to factor (except for the numerator but there's no point in doing so because the denominator isn't factorable)

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

are you sure the expression is `(x^2-9)/(x^3+3)` ?

OpenStudy (anonymous):

limit as x approaches negative three of quantity x squared minus nine divided by quantity x cubed plus three.

jimthompson5910 (jim_thompson5910):

so the only thing you can do really is plug in x = -3 which is an algebraic move

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