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Find the limit of the function algebraically. limit as x->-3 of (x^2-9)/(x^3+3)
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See what happens when you do direct substitution. Replace every copy of x in `(x^2-9)/(x^3+3)` with -3 and then simplify. What do you get?
0/-27
it says algebraically tho
Which turns into 0. So the final answer is 0.
yes that was done algebraically. There's nothing to factor (except for the numerator but there's no point in doing so because the denominator isn't factorable)
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@jim_thompson5910
are you sure the expression is `(x^2-9)/(x^3+3)` ?
limit as x approaches negative three of quantity x squared minus nine divided by quantity x cubed plus three.
so the only thing you can do really is plug in x = -3 which is an algebraic move
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