how many liters of water have been pumped into the tank from t=0 to time=55?
so this is pretty much taking the derivative and then evaluating it at x= 45
how would you take the derivative of something when there isn't a function?
The graph looks like a funtion. passes vertical line test. Also at time(45) the graph is moving in a linear fashion. We know that when you take the derivative of a linear equation the derivate will in result be the slope of line. Looks like what you did is alright.
okay but how would l find how many liters of water have been pumped into the tank from t=0 to t=55?
Is that part of the question?
yup
idk maybe that involves integration/ finding the area under the curve. tbh im really not sure
I tried that and what I get goes over 100 liters...
Hmm, could it be adding 3 'derivatives'? I know from 20 to 35 minutes, it was at a constant, which is 30.. so we would just do \[(30)(15)\] which will be over 100, which makes sense. It's pumping at 30 a minute during a time period and we want 55 minutes worth. (Remember, it doesn't hold 100 liters, it starts out with 100) For the first part, it looks like a trapezoid and the last part looks like a triangle, so maybe find the area of those, as sweetburger said
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