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A combined circuit has two resistors in parallel (6.0 ohms and 8.0 ohms) and another in series (13.0 ohms). If the power source is 9.0 volts, what will the current be?
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You have to combine all the resistor first: For parallel resistors you use the formula: \(\sf 1/R_{eq} =1/R_1 + 1/R_2 + ...\) For series resistor you use the formula \(\sf R_{eq} = R_1 + R_2 + ...\) So for your problem, you have TWO parallel resistors, so calculate the equivalent resistor and then just add the other resistor.
After you find the \(\sf R_{total}\) , you can apply Ohm's Law: \(\sf I= V/R_{total}\) , to get the current.
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