Physics 12 Question! Circuits: I know the answer to part a and part b. For part c use the formula => P= IV or P= (I^2)(R)
For part c, the answer is 0.11 W. My teacher told me, but I don't understand why I have to follow this method, could you please clarify it for me. Thank you. V3=IR3 V3=(0.33 A)(100ohms)= 3.3 v P= IV3 P= (0.33)(3.3)=0.1089 W
You're tying to find the power dissipated through the 100 ohm resistor. the formula you're teacher gave you basically says from top to bottom: V3 = IR3 the current through R3 (100 ohm resistor) found in question 2 is multiplied through to find the voltage. Then use the power formula to find the power dissipated through the resistor P=IV3 P = (current)(voltage through R3) P= (0.33 A) (3.3V) = .1089 which rounds out to about .11W.
P= (I^2)(R) leads to the same answer. It is also correct.
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