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Chemistry 13 Online
RhondaSommer (rhondasommer):

What is the molar ratio for the following equation after it has been properly balanced? ____SiO2 + ____C --> ____ SiC + ____CO Reactants: SiO2 = 1, C = 3; Products: SiC = 1, CO = 2 Reactants: SiO2 = 1, C = 2; Products: SiC = 1, CO = 2 Reactants: SiO2 = 2, C = 3; Products: SiC = 2, CO = 2 Reactants: SiO2 = 3, C = 3; Products: SiC = 3, CO = 2

OpenStudy (stargazer412):

The answer is SiO2+3C-->SiC+2CO Because it gives you 1Si, 3C,and 2O per side. Just make sure as you do them to add up your products' parts so they are even to the reactants' parts.

RhondaSommer (rhondasommer):

@sweetburger Im really confused! I can seem to be able to post any questions! There is no post button!

OpenStudy (sweetburger):

wooow that is weird

OpenStudy (sweetburger):

I dont even know how to fix that.

RhondaSommer (rhondasommer):

I have restarted my computer, logged out and in OS and ughhh

OpenStudy (sweetburger):

so you can type in your question but the post option never pops up :/

RhondaSommer (rhondasommer):

nope. Im so frustrated! I have questions too!

RhondaSommer (rhondasommer):

I told a mod *cough cough* @mathmale and gotten no answers

OpenStudy (sweetburger):

i just asked in global chat and got ignored -_-

OpenStudy (sweetburger):

Ill message a couple of moderators see if i can get you some help.

RhondaSommer (rhondasommer):

thanks :)

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