Mathematics
11 Online
OpenStudy (jekdidkdjrjrjjr):
fan+medal easy
see pic
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OpenStudy (jekdidkdjrjrjjr):
OpenStudy (jekdidkdjrjrjjr):
@reemii @Error1603
OpenStudy (reemii):
hint: “\(z\) and \(\bar z\)”
OpenStudy (jekdidkdjrjrjjr):
i don’t get it
OpenStudy (jekdidkdjrjrjjr):
??
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OpenStudy (superteenblue):
me either
OpenStudy (jekdidkdjrjrjjr):
anyone??
OpenStudy (delirium):
They don't exist? hold on, revving up thought processes
OpenStudy (jekdidkdjrjrjjr):
giving anyone with the right answer a medal
OpenStudy (jekdidkdjrjrjjr):
is anyone still trying??
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OpenStudy (delirium):
me
OpenStudy (jekdidkdjrjrjjr):
thanks!
OpenStudy (reemii):
Example. \(x^2 = -16\). Solutions: \(z=4i\) and \(\bar z =-4i\). (\(\bar z\) is complex conjugate).
Does the hint above make more sense?
OpenStudy (jekdidkdjrjrjjr):
i need the answer otherwise I’m not giving a medal
OpenStudy (delirium):
How did you come up with those numerical values @reemi?
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OpenStudy (jekdidkdjrjrjjr):
first one to answer gets a medal
OpenStudy (delirium):
A quadratic equation with two identical roots is said to have a multiplicity of two zeroes.
OpenStudy (delirium):
Your equation has two roots (two instances of x)
OpenStudy (jekdidkdjrjrjjr):
so what’s the final answer?
OpenStudy (delirium):
I just gave it to you. Since there are two instances of x in the quadratic equation, there will be two zeroes calculable.
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OpenStudy (jekdidkdjrjrjjr):
ok ty ill tag u
OpenStudy (delirium):
*two real zeroes calculable
OpenStudy (delirium):
thnx