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Mathematics 11 Online
OpenStudy (jekdidkdjrjrjjr):

fan+medal easy see pic

OpenStudy (jekdidkdjrjrjjr):

OpenStudy (jekdidkdjrjrjjr):

@reemii @Error1603

OpenStudy (reemii):

hint: “\(z\) and \(\bar z\)”

OpenStudy (jekdidkdjrjrjjr):

i don’t get it

OpenStudy (jekdidkdjrjrjjr):

??

OpenStudy (superteenblue):

me either

OpenStudy (jekdidkdjrjrjjr):

anyone??

OpenStudy (delirium):

They don't exist? hold on, revving up thought processes

OpenStudy (jekdidkdjrjrjjr):

giving anyone with the right answer a medal

OpenStudy (jekdidkdjrjrjjr):

is anyone still trying??

OpenStudy (delirium):

me

OpenStudy (jekdidkdjrjrjjr):

thanks!

OpenStudy (reemii):

Example. \(x^2 = -16\). Solutions: \(z=4i\) and \(\bar z =-4i\). (\(\bar z\) is complex conjugate). Does the hint above make more sense?

OpenStudy (jekdidkdjrjrjjr):

i need the answer otherwise I’m not giving a medal

OpenStudy (delirium):

How did you come up with those numerical values @reemi?

OpenStudy (jekdidkdjrjrjjr):

first one to answer gets a medal

OpenStudy (delirium):

A quadratic equation with two identical roots is said to have a multiplicity of two zeroes.

OpenStudy (delirium):

Your equation has two roots (two instances of x)

OpenStudy (jekdidkdjrjrjjr):

so what’s the final answer?

OpenStudy (delirium):

I just gave it to you. Since there are two instances of x in the quadratic equation, there will be two zeroes calculable.

OpenStudy (jekdidkdjrjrjjr):

ok ty ill tag u

OpenStudy (delirium):

*two real zeroes calculable

OpenStudy (delirium):

thnx

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