MEDAL for help in Algebra 1! Simplify the following...
\[\large \frac{x+8}{27x^3 - 9x^2} - 3\]
first step is getting the terms to have a common denominator
The common denominator is 27x^3 - 9x^2
yep
So should I factor it?
no not yet
Ok.
your going to be expanding so might as well not factor it
So the first fraction you leave the numerator as it is. Second fraction, 3(27x^3 -9x^2) = 81x^3 - 27x^2
yep looks good. dont forget the negative sign though
oh yes so then it would be -81x^3 + 27x^2
yep and now you can combine the numerator over the single denominator
\(\huge \frac{x + 8 -81x^2 + 27x^2 }{27x^3 - 9x^2}\)
looks good except the term -81x^2 i think should be -81x^3
Oh yes. But don't I need to factor the denominator? It doesn't look too simplified
@sweetburger @agent0smith @ganeshie8 @KamiBug
if you factor the denominator what are you going to do with it? Unless you determine that you could possibly factor the numerator and cancel something out?
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