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OpenStudy (calculusxy):
MEDAL for help in Algebra 1!
Simplify the following...
10 years ago
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OpenStudy (calculusxy):
\[\large \frac{x+8}{27x^3 - 9x^2} - 3\]
10 years ago
OpenStudy (sweetburger):
first step is getting the terms to have a common denominator
10 years ago
OpenStudy (calculusxy):
The common denominator is 27x^3 - 9x^2
10 years ago
OpenStudy (amilapsn):
yep
10 years ago
OpenStudy (calculusxy):
So should I factor it?
10 years ago
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OpenStudy (sweetburger):
no not yet
10 years ago
OpenStudy (calculusxy):
Ok.
10 years ago
OpenStudy (sweetburger):
your going to be expanding so might as well not factor it
10 years ago
OpenStudy (calculusxy):
So the first fraction you leave the numerator as it is.
Second fraction, 3(27x^3 -9x^2) = 81x^3 - 27x^2
10 years ago
OpenStudy (sweetburger):
yep looks good. dont forget the negative sign though
10 years ago
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OpenStudy (calculusxy):
oh yes so then it would be -81x^3 + 27x^2
10 years ago
OpenStudy (sweetburger):
yep and now you can combine the numerator over the single denominator
10 years ago
OpenStudy (calculusxy):
\(\huge \frac{x + 8 -81x^2 + 27x^2 }{27x^3 - 9x^2}\)
10 years ago
OpenStudy (sweetburger):
looks good except the term -81x^2 i think should be -81x^3
10 years ago
OpenStudy (calculusxy):
Oh yes. But don't I need to factor the denominator? It doesn't look too simplified
10 years ago
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OpenStudy (calculusxy):
@sweetburger @agent0smith @ganeshie8 @KamiBug
10 years ago
OpenStudy (sweetburger):
if you factor the denominator what are you going to do with it? Unless you determine that you could possibly factor the numerator and cancel something out?
10 years ago
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