Can someone help me please Part 1. Using the two functions listed below, insert numbers in place of the letters a, b, c, and d so that f(x) and g(x) are inverses. f(x)=x+a/b g(x)=cx-d Part 2. Show your work to prove that the inverse of f(x) is g(x). Part 3. Show your work to evaluate g(f(x)). Part 4. Graph your two functions on a coordinate plane. Include a table of values for each function. Include 5 values for each function. Graph the line y = x on the same graph.
can someone help me please
You should pick simple numbers for a and b
a is 6 and b is 9
by the way is it \[ f(x) = x + \frac{a}{b} \] or \[ f(x) = \frac{x+a}{b} \]
also, life is a bit easier if you use *small numbers* like 1 and 2!
we could use the second one
sure
It makes a difference to the answer. can you use the equation editor to post the exact equations for f(x) and g(x) ? otherwise, we do a lot of work and get the wrong answer.
f(x)=x+1/2
and is that x plus one-half or (x+1) all divided by 2 ?
\[f(x)=\frac{ x+a }{ b}\]
\[g(x)=cx-d\]
ok, so you should write it as f(x) = (x+1)/2 to find the inverse, rename f(x) as y y= (x+1)/2 (and remember this , because they want you to plot this line) next, "swap the x and y" can you do that ?
swap means erase the "y" and put x in its place then erase the original "x" and put in y what do you get ?
y=1/2+1 i guess
start with y= (x+1)/2 change the first "y" into x what do you get ?
Is this the segment honors project?
yes
then in the (x+1) change that "x" into a y
i confused
the procedure to find the inverse has a few steps the first step is to "rename" x to y and the y to x there is no thinking involved. If you see y, write x, if you see x write y start with y = (x+1)/2
and leave all the other "stuff" as it is
x=(y+1)/2
yes
the next step is "solve for y" I would start by multiplying both sides by 2 that means write *2 on both sides (that means times 2)
x(y+1)/4
it is clearer if you write it like this \[ x = \frac{y+1}{2} \\ 2\cdot x = 2\cdot \frac{y+1}{2} \]
in algebra we don't usually show the multiply sign when we do number times letter we would write 2*x as just 2x
on the right side you have a 2 "up top" and a 2 "down below" that means you have \[ \frac{2}{2} \] do you know what that simplifies to ?
1
yes, so the right side is the same as 1*(y+1) which is just (y+1) so far you have \[ 2x= (y+1)\] the parens are not doing anything so it is the same as \[ 2x = y+1 \] or \[ y+1= 2x \]
next, write -1 on both sides what do you get ?
2(1)=1+1
start with y+1 = 2x write -1 on each side don't do anything else. what does it look like?
1+1=2x
1+=2(1)
no, we leave the y alone you have y+1 = 2x now write -1 on both sides, like this y+1 -1 = 2x -1
on the left side you have 1 take away 1
1 -1 is 0 y+0 is y (adding 0 does not do anything) you're answer is y= 2x-1 the last step is rename y to be g(x)
g(x)= 2x - 1 now you know what 'c" and "d" are, by matching your answer with g(x)= cx - d
thanks you so much phi
Join our real-time social learning platform and learn together with your friends!