Question

Find the angle between the given vectors to the nearest tenth of a degree.

u = <2, -4>, v = <3, -8>

Answer 1

answer choices

3.0°
6.0°
-7.0°
16.0°

Answer 2

Hint: $$u.v = |u| |v| \cos \theta$$

Answer 3

so would i add the 2 numbers in u together and in v

Answer 4

first evaluate the dot product
we could solve for \( \theta \)

Answer 5

im so lost in this question sorry. how would i begin by solving this

Answer 6

@ashking we we can solve for theta
\[ \Large{\sf u.v = |u| |v| \cos \theta
\\ \quad \\ \frac{u.v}{|u| |v| } = \cos \theta
\\ \quad \\ \theta = \cos \left( \frac{u.v}{|u| |v| } \right)^{-1}
}\]

Answer 7

alright so the equation is changed to solve the problem a theta is the degrees do i begin plugging in number

Answer 8

Yes. I assume you know what ' u.v ' and |u| mean.

Answer 9

alright so i am at 38/2sqrt365\[38/2 \sqrt365\]

Answer 10

i got it its 6.0

Answer 11

Nice work .