What is 3 root of 250? A. 5 3 root of 2 B. 2 3 root of 5 C. 5 3 root of 3 D. 3 3 root of 5
hint \[\LARGE \sqrt[3]{250}=\sqrt[3]{125*2}\] I'm picking on 125 because 5^3 = 5*5*5 = 125
You were on this questions hours ago, and I gave you the same hint that Jim gave you. Here's a new one: \(\Large\bf \sqrt[3]{x^3} = x\)
i know i closed re posted it i think B
Why do you think it is B? How did you pull out 2 from the cube root? You can only pull out 2 if it was inside the cube root three times, like 2 * 2 * 2.
HMM my second final guess is D
\[\LARGE \sqrt[3]{250}=\sqrt[3]{125*2}\] \[\LARGE \sqrt[3]{250}=\sqrt[3]{125}*\sqrt[3]{2}\] \[\LARGE \sqrt[3]{250}=\sqrt[3]{5^3}*\sqrt[3]{2}\] I'll let you finish
I'm using the rule \[\LARGE \sqrt[n]{x*y} = \sqrt[n]{x}*\sqrt[n]{y}\]
I need this done C
@jim_thompson5910
what is \[\LARGE \sqrt[3]{5^3}\] equal to?
D right?
please stop randomly guessing
what is \[\LARGE \sqrt[3]{5^3}\] equal to?
my brain hurts sorry i want this done as quickly as possible
A
The 3s will cancel \[\LARGE \sqrt[3]{5^3} = \sqrt[{\color{red}{3}}]{5^{{\color{red}{3}}}}\] \[\LARGE \sqrt[3]{5^3} = \sqrt[{\color{red}{\cancel{3}}}]{5^{{\color{red}{\cancel{3}}}}}\] and so does the radical as well
Which is why \[\LARGE \sqrt[3]{5^3}=5\]
okay so
\[\LARGE \sqrt[3]{250}=\sqrt[3]{125*2}\] \[\LARGE \sqrt[3]{250}=\sqrt[3]{125}*\sqrt[3]{2}\] \[\LARGE \sqrt[3]{250}=\sqrt[3]{5^3}*\sqrt[3]{2}\] \[\LARGE \sqrt[3]{250}=5*\sqrt[3]{2}\]
but the closet it seams i get to that is B
23.6440219392 @jim_thompson5910
I already got to the final answer on the last line
Oh XD i thought you wanted me to multiply that oops
no the teacher wants you to leave it in exact radical form
thanks for the help im already a fan and i meddled you Thank alot man
you're welcome
i got one more
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