Please help with me with my math homework 3. Ms. Jones keeps her pigs in a fenced pen that has the shape of a regular pentagon. The area of the pen is 50 ft2 and the apothem is 4 ft. Ms. Jones has decided that she wants to remake the pig living area to be in the shape of a rectangle instead. She wants to reuse the same amount of fence to make the new rectangular living space. Ms. Jones wants to give the pigs as much living space as possible. What should the dimensions and the area of the rectangular space be in order to provide the most area with the given amount of fence? Ms. Jone
Ok so the area for polygons is \[\frac{ 1 }{ 2 }ap=A\] Where A= area, a=apothem, and p is the perimeter
So it gives you the area and apothem and you have to find the perimeter So \[\frac{ 1 }{ 2 }4p=50\]What does the perimeter equal
10 @Brill
Umm no try again, multiply your 4 first then divide
*multiply your 4 by the 1/2 first
ok, 2p=50 25
Right So the Isoperimetric Theorem says that squares ( which are also rectangles) have greater area than rectangles of the same perimeter So that means you have to make a square out of 25 ft of fence as your perimeter
Ofcourse the problem is flawed because the square would give less area than the pentagon because of the same theorem
so if the perimeter is 25, then 25 divided by 4 would get you one side right?
um give me a minute, I'll tag you then
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