How would you factor m^2+m+1/4? Please show steps.
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OpenStudy (daniel.ohearn1):
(m^2) + (m) + (1/4) is what you want factored?
OpenStudy (daniel.ohearn1):
The terms in the function are the first of all.
OpenStudy (daniel.ohearn1):
That would be different from (m^2)+((m+1)/4)
or ((m^2)+(m+1))/4
OpenStudy (sen_turtle):
(m^2)+(m)+(1/4)
OpenStudy (daniel.ohearn1):
(m+2)(m-1) would give you your second m when multiplied, then all you need is to make turn the -2 into 1/4
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OpenStudy (daniel.ohearn1):
1st account for your m^2 and m terms
OpenStudy (daniel.ohearn1):
Actually alternatively you could even factor it evenly into 2 factors. m must be in both factors to get m^2 you know. Then they other numbers will be add up to 1 and multiply together to get (1/4). Can you think of those 2 numbers?
OpenStudy (sen_turtle):
Would that answer be 1/2?
OpenStudy (daniel.ohearn1):
Yes
OpenStudy (daniel.ohearn1):
Acknowledging the formula for factoring (a^2)+(2ab)+(b^2)=(a+b)(a+b)
In this situation 2ab= 1m and a^2 = 1m^2 therefore 2b=1m b=1/2 since a=m=1