What are the solutions to the equation y² –1 = 24? Choose all answers that are correct. A. 5 B. 12.5 C. –5 D. –12.5 C?
\[y^2-1=24\] \[\mathrm{Subtract\:}24\mathrm{\:from\:both\:sides}\] \[y^2-25=0\]
@Spicytaco1 can you solved the Equation
B?
no
Solve the Equation using factoring and completing square and quardaic formula... use any method
a and c
y = +5 and y = -5
\[\mathrm{Solving\:with\:the\:Quadratic\:Formula}\] \[\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\] \[\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\] \[\mathrm{For\:}\quad a=1,\:b=0,\:c=-25:\quad y_{1,\:2}=\frac{-0\pm \sqrt{0^2-4\cdot \:1\left(-25\right)}}{2\cdot \:1}\] \[y=\frac{-0+\sqrt{0^2-4\cdot \:1\cdot \left(-25\right)}}{2\cdot \:1}=5\] \[y=\frac{-0-\sqrt{0^2-4\cdot \:1\cdot \left(-25\right)}}{2\cdot \:1}=-5\] \[y=5,\:y=-5\]
can you help me with one more?
yes
ok
What are the square roots of 484? A. −12 and 12 B. −18 and 18 C. −22 and 22 D. −242 and 242
\[\sqrt{484}\] \[\mathrm{Factor\:the\:number:\:}\:484=22^2\] \[=\sqrt{22^2}\] \[\sqrt{22^2}=22\]
Thanks :D
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