Divide the following polynomial, then place the answer in the proper location on the grid. Write the remainder as a fraction. (2a 2 + a + 3) (a - 1)
@ganeshie8
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how many |dw:1461172988359:dw|
how many times can A go into 2A^2 ?
4 times?
No, It goes in 2A times. 2a * a = 2a^2
So, you write in 2a at the top, like so: And multiply (a-1) by 2a, like so: |dw:1461173370884:dw|
Then, subtract *2a^2* from *2a^2 +a +3 |dw:1461173415403:dw|
Are you following me?
anyway, a goes into 3a, three times:|dw:1461173753584:dw| Hence, multiply the divisor by 3 and subtract from the remainder left over from the last operation. Add 3 to the top line as you multiplied the divisor by +3. You're left with 6 as a remainder.
You can't divide the remainder further. When this is the case the resultant fraction is the remainder over the divisor. ex: the numerator is the remainder, and the divisor is the denominator. The answer is: 2a +3 Remainder: 6/a-1 (Apologies, I wrote -1 instead of -3.) remainder: 6/ (a-1)|dw:1461173901021:dw|
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