Question

What is the result of isolating y2 in the equation below?

(x - 2)2 + y2 = 64

A. y2 = -x2 + 4x + 4
B. y2 = 64 - x2
C. y2 = x2 + 4x + 60
D. y2 = -x2 + 4x + 60

Answer 1

You can re-write it like this

\[y^{2}+(x-2)^{2} = 64 \]

Answer 2

B?

Answer 3

We need to expand (x-2)^2 first too.

\[(x-2)^{2} = x^{2}-4x+4 \]

\[y^{2}+x^{2}-4x+4 = 64\]

Answer 4

where are the 4´s coming from

Answer 5

we needed to expand (x-2)^2 that's why

Answer 6

ok how do u expand it

Answer 7

\[(x-2)(x-2) \]

Answer 8

what is x

Answer 9

you foil it

Answer 10

when i put that in i got -79200

Answer 11

\[x^{2}-4x+4 = (x-2)(x-2)\]

Answer 12

i still dont know where the 4x+4 came from

Answer 13

this is what we end up with

\[y^{2}+x^{2}-4x+4 = 64\]