Proving trig functions with substitution I understand that I need to substitute in trig identities, but I don't understand the steps to do it. Questions: https://gyazo.com/940b577311db9eba1a525de731d0b661 Trig identities to use: https://gyazo.com/95a7016e9594eddf96e7927561f2b6d0
We want to show one side is the other side. Let's look at the first one and try to show the left hand side is the right hand side
\[\cot(x) \sec^4(x)\] try using a Pythagorean identity and then expanding
In doing this would you be, for example, dividing it by a term? Or is this the result of it?
Not sure what you mean you know that sec^4(x) is the same as (sec^2(x))^2 so you can use a Pythagorean identity to write this part in terms of tan(x)
So because you have sec^2 in the equation, you would be able to "pull it out" (don't know how to really explain it" and use the identity sec^2u = 1 + tan^2u?
yes replace sec^2(x) with 1+tan^2(x)
you will have a binomial to expand and then multiply that product by the cot(x) factor you have
\[\cot(x) (\sec^2(x))^2 \\ \cot(x)(\sec^2(x))^2 \\ \text{ use } \sec^2(x)=\tan^2(x)+1\]
Ok. That was confusing me. I was trying to figure out where that came from.
can you show me how far you have gotten
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