find the x and y intercept for the following equation and write an ordered pair for each, round if necessary 2x+3y=6
The x-intercept is where the line crosses the x-axis. To get on the x-axis, the y-value of the x-intercept must be 0. 2x+3y=6 x-intercept Let y = 0 2x + 3*0 =6 Solve this for x.
2x+0=6?
then you subtract 0 from both sides?
then 2x=6 then x=3
@Directrix
You are correct :)
The x-intercept has coordinates (3,0)
how do i find y intercept
plug in 0 for x
The y-intercept is on the y-axis. To get on the y-axis, the x-coordinate must be 0.
and you do the same thing as in the other equation
Solve for y: 2x+3y=6 Let x = 0 2*0 + 3y = 6 y = ?
0+3y=6 what do i do from there do i sub 6 or 3 from both sides
3y = 6 y = ?
y=2 so y int (2,0)
Coordinates of y-intercept: (0,2)
>>so y int (2,0) No. That point is on the x-axis. The y-intercept is on the y-axis and has x-coordinate 0.
because (x,y) rules :)
yes and thanks its right answer
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