find the x and y intercept for the following equation and write an ordered pair for each, round if necessary
2x+3y=6
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Directrix (directrix):
The x-intercept is where the line crosses the x-axis.
To get on the x-axis, the y-value of the x-intercept must be 0.
2x+3y=6
x-intercept
Let y = 0
2x + 3*0 =6
Solve this for x.
OpenStudy (pphalke):
2x+0=6?
OpenStudy (pphalke):
then you subtract 0 from both sides?
OpenStudy (pphalke):
then 2x=6 then x=3
OpenStudy (pphalke):
@Directrix
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OpenStudy (hyperpiper):
You are correct :)
Directrix (directrix):
The x-intercept has coordinates (3,0)
OpenStudy (pphalke):
how do i find y intercept
OpenStudy (hyperpiper):
plug in 0 for x
Directrix (directrix):
The y-intercept is on the y-axis.
To get on the y-axis, the x-coordinate must be 0.
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OpenStudy (hyperpiper):
and you do the same thing as in the other equation
Directrix (directrix):
Solve for y:
2x+3y=6
Let x = 0
2*0 + 3y = 6
y = ?
OpenStudy (pphalke):
0+3y=6
what do i do from there do i sub 6 or 3 from both sides
Directrix (directrix):
3y = 6
y = ?
OpenStudy (pphalke):
y=2
so y int (2,0)
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Directrix (directrix):
Coordinates of y-intercept: (0,2)
Directrix (directrix):
>>so y int (2,0)
No. That point is on the x-axis.
The y-intercept is on the y-axis and has x-coordinate 0.