Question

Will medal! Using a directrix of y = 2 and a focus of (3, -4), what quadratic function is created?

Answer 1

@InstagramModel @phi @Directrix @AloneS @kiwibyrd anyone???

Answer 2

These are the options:
f(x) = 1/12 (x-3)^2 -1
f(x) = -1/6 (x+3)^2 +1
f(x) = 1/6 (x-3)^2 + 1
f(x) = -1/12 (x-3)^2 -1

Answer 3

uhhhh i dont know how to do these but if you go to mathway.com and type in all of the equations, you can check one by one to see which one matches the directrix and focus

Answer 4

okay thanks for responding!

Answer 5

hey i can see if i can help ok

Answer 6

thank you @therawbugeyes please

Answer 7

so do you know how to set this up?

Answer 8

no, but i found the vertex?

Answer 9

ok and what did you get?

Answer 10

(0, -1) if i did it correct

Answer 11

thats what i got

Answer 12

where do i go from there?

Answer 13

here try this link it should help you ok http://jwilson.coe.uga.edu/emt668/EMAT6680.2002.Fall/Ledford/Ledford6/parabola.html

Answer 14

hey since your here can you see if you can help me?

Answer 15

i can try

Answer 16

ok cool thxs:)

Answer 17

The equation below represents Function A and the graph represents Function B:

Function A

f(x) = 6x – 1

Function B

graph of line going through ordered pairs 1, 4 and negative 1, negative 2 and negative 2, negative 5

Which equation best compares the slopes of the two functions?
Slope of Function B = 2 x Slope of Function A.
Slope of Function A = Slope of Function B
Slope of Function A = 2 x Slope of Function B
Slope of Function B = – Slope of Function A

Answer 18

did you get it?

Answer 19

I tried but I've never seen anything like that @therawbugeyes sorry :/ not multiplying slopes