Find the volume of the solid generated when the region between the graphs f(x) = 2 sqrt(sinx) and y = 0 over the interval [0,pi] is revolved around the x-axis

Question

satellite73 · Answer

http://www.wolframalpha.com/input/?i=2sqrt%28sin%28x%29%29+domain+0..pi

satellite73 · Answer

that is just a picture of the region 
not the volume

satellite73 · Answer

itegrate $\pi r^2$ (the area of the circle) from $0$ to $\pi$
in your case it should not be hard because $r=f(x)=2\sqrt{\sin(x)}$

satellite73 · Answer

*integrate

amenah8 · Answer

the anti-derivative would be -4cosx+C

satellite73 · Answer

forget the C it is  a definite integral

satellite73 · Answer

but yes, when you square and find the anti - derivative it is $-4\cos(x)$

satellite73 · Answer

oh don't forget the $\pi$

amenah8 · Answer

so is the anser 4pi?

amenah8 · Answer

because on my answer sheet they got 8pi

satellite73 · Answer

it is $8\pi$

satellite73 · Answer

$$-4\pi \cos(x)|^{\pi}_0$$
$$=-4\pi(\cos(\pi)-\cos(0))$$

satellite73 · Answer

$$=-4\pi(-1-1)$$ etc

amenah8 · Answer

oh! i forgot to plug in 0

satellite73 · Answer

yeah you need that one too!

amenah8 · Answer

thank you! that really helped