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OpenStudy (sweetburger):
Yea, im alright at it.
RhondaSommer (rhondasommer):
hallelujah
OpenStudy (sweetburger):
lol :P
RhondaSommer (rhondasommer):
Given the reaction, Fe2O3 + 3 CO ➡ 2 Fe + 3 CO2, if 12.0 moles of CO2 are made, then how many moles of CO were used?
12.0 moles
6.0 moles
4.0 moles
3.0 moles
RhondaSommer (rhondasommer):
and then how do I know?
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OpenStudy (sweetburger):
So we just work backwards here. I will set it up so you can see how to do these |dw:1461285172826:dw|
OpenStudy (sweetburger):
|dw:1461285248288:dw|
OpenStudy (sweetburger):
So you can basically ignore the 3/3 because it equals 1 so you are left with 12 moles of CO
RhondaSommer (rhondasommer):
how do they cross out if one is CO2 and one is just CO?
OpenStudy (sweetburger):
I only crossed out moles of CO2. The moles of CO was left untouched.
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RhondaSommer (rhondasommer):
ohhh and the 3's themselve are just one. I C I C
OpenStudy (sweetburger):
yes very good.
RhondaSommer (rhondasommer):
what about the 2 mole of FE?
OpenStudy (sweetburger):
"what 2 moles of Fe?" No, but seriously if the question doesn't say anything about the 2 mole of Fe you can just ignore it.
OpenStudy (sweetburger):
You are specifically observing CO and CO2. Nothing Else.
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RhondaSommer (rhondasommer):
oh ok :)
OpenStudy (sweetburger):
need help with any others?
RhondaSommer (rhondasommer):
it was 12.0 right?
OpenStudy (sweetburger):
yes correct :)
RhondaSommer (rhondasommer):
okay so the next one is wierd because it actually combines the elements... I'll tag you :)
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