Question

Red mercury (II) oxide decomposes to form mercury metal and oxygen gas according to the following equation: 2HgO (s) ➡ 2Hg (l) + O2 (g). If 4.00 moles of HgO decompose to form 1.50 moles of O2 and 603 g of Hg, what is the percent yield of this reaction?

26.7%

53.4%

75.0%

95.5%

Answer 1

@sweetburger

Answer 2

how do I know what it is sean?

Answer 3

Actual yield/theoretical yield x 100

Answer 4

4 moles of 2HgO should produce 2 moles of O2. So that is our theoretical yield. The actual yield is 1.5 moles of O2 so 1.5/2 x 100 = ?

Answer 5

c?

Answer 6

p.s. after this question i need to take a 1/2 hour break. will you still be on?

Answer 7

yes c is correct

Answer 8

idk i might be. I have to study for an ap bio and calc final

Answer 9

maybe an hour? could you be back in an hour?

Answer 10

.-. pleeease I neeed you

Answer 11

if im not asleep ill try to be

Answer 12

okay :) <3 thanks

Answer 13

your a lifesaver

Answer 14

if you dont see me ill gladly help tommorow

Answer 15

thank you :)

Answer 16

np my pleasure :D

Answer 17

:D

Answer 18

@sweetburger can you help out?

Answer 19

sure

Answer 20

Yay :D