~~I'll give a medal :))~~
Find an equation for the line that passes through the points, (3,−2) and , (−3,6).
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OpenStudy (ashleyy_smith):
@FortyTheRapper
OpenStudy (nubeer):
do you know how to find a gradient?
OpenStudy (ashleyy_smith):
no :( @nubeer
OpenStudy (nubeer):
\[m=\frac{ y _{2} -y _{1}}{ x _{2}-x _{1} }\]
"m" is the gradient here
OpenStudy (ashleyy_smith):
oh okay. How would I plug in the numbers
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OpenStudy (nubeer):
(3,-2) -- > these are x1 and y1 x1=3,y1=-2
(-3,6) x2=-3,y2=6
OpenStudy (nubeer):
i believe you can find "m" now
OpenStudy (ashleyy_smith):
I got - 8/6
OpenStudy (ashleyy_smith):
@nubeer
OpenStudy (nubeer):
gud.
now to find any equation of line the formula is as following:
\[y=mx + c\]
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OpenStudy (nubeer):
you have found m right?
OpenStudy (ashleyy_smith):
Oh that's the answer? :O
OpenStudy (nubeer):
no :3
OpenStudy (nubeer):
i am jut trying to explain you step by step
OpenStudy (ashleyy_smith):
oh y = mx + c
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OpenStudy (nubeer):
m = -8/6 (as you found above)
y=mx+c
now plug m here
OpenStudy (ashleyy_smith):
I dont get it :s
OpenStudy (nubeer):
:/
OpenStudy (nubeer):
which part u don't get?
OpenStudy (ashleyy_smith):
what I have to plug in y = mx + c
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OpenStudy (nubeer):
the value "m" you just found above
OpenStudy (nubeer):
m is also known as gradient
OpenStudy (ashleyy_smith):
do I have to do something with that to get mx??
OpenStudy (nubeer):
-_-
let me start over again
OpenStudy (nubeer):
you have two coordinates given to you in question..
i asked you to find the gradient.
you got -8/6
so far correct?
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OpenStudy (ashleyy_smith):
yes
OpenStudy (nubeer):
okay.. this was only the half solution..
so the next step is to know the formula to find the equation of line (which is asked in your question)
Basically there are two formulas to find the equation of line
\[y=mx+c\]
OR
\[y-y _{1}=m(x-x _{1})\]
Are you familiar or studied any one of them at school or anywhere?
OpenStudy (ashleyy_smith):
no not yet :s
OpenStudy (nubeer):
okay.. well you can remember it now that you have to use any one of the formula above.
so which formula you would like to choose?
OpenStudy (ashleyy_smith):
which one is easier? :o
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OpenStudy (nubeer):
both are..
but for starters u can use y=mx+c
OpenStudy (ashleyy_smith):
oh okay
OpenStudy (nubeer):
y=mx + c
here we usually have to find "m" and "c"
we did find "m"
what was it?
OpenStudy (ashleyy_smith):
-8/6
OpenStudy (nubeer):
okay now we plug this value in y=mx+c
y = (-8/6)x +c
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OpenStudy (nubeer):
now only the missing variable is c
pick any coordinate given in your question
OpenStudy (ashleyy_smith):
ummm 3, -2
OpenStudy (nubeer):
okay.. put them in the equation now..
y= (-8/6)x +c
find c here
OpenStudy (ashleyy_smith):
y= (-8/6)3 + -2?
OpenStudy (nubeer):
:3 no
x =3, y=-2
pluggin in equation
-2 = (-8/6) (3) +c
-2 = -4 +c
c =2
so
y= (-8/6)x +2
this is your answer
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