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Mathematics 16 Online
OpenStudy (howard-wolowitz):

my question is in the comments, medal for your help

OpenStudy (issachall):

the other two are as follows: 1/2 1/8 im not sure about 1/8 though

OpenStudy (phi):

yes, greater than 5 is 6,7 or 8 each has the same chance ⅛ that we can add up: ⅜

OpenStudy (phi):

Pr( x <= 4) means Pr of 1,2,3 or 4 add up those probabilities

OpenStudy (howard-wolowitz):

ok so we agree the first is 3/8 good now for the second one i need you to show me how to do that

OpenStudy (howard-wolowitz):

what am i adding up

OpenStudy (phi):

you add up the P(1) + P(2) +P(3) + P(4) they are all ⅛ so it's not too hard

OpenStudy (phi):

the mean is found by adding up X * P(X) for all the x's notice this is the same as adding up the x's , and then dividing by 8

OpenStudy (howard-wolowitz):

so for the second one it should be 4/8

OpenStudy (phi):

yes P(x<=4) is 4/8 but I would simplify that to ½

OpenStudy (howard-wolowitz):

ok and for the mean is 1

OpenStudy (howard-wolowitz):

its either 1 or 1/8

OpenStudy (howard-wolowitz):

@phi

OpenStudy (phi):

the easy way to find the mean when all of the numbers have the *same* probability is to first add up the numbers then multiply by ⅛ what is the sum of the numbers ?

OpenStudy (howard-wolowitz):

the sum is 36

OpenStudy (phi):

yes, now multiply by ⅛ to get the mean ⅛ * 36 or 36/8 is the answer. it simplifies to 4.5

OpenStudy (howard-wolowitz):

i got 4.5

OpenStudy (phi):

yes

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