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Mathematics 21 Online
OpenStudy (18jonea):

Help please

OpenStudy (18jonea):

OpenStudy (18jonea):

@welshfella

OpenStudy (18jonea):

@mathmale

OpenStudy (welshfella):

have you measured the lengths?

OpenStudy (18jonea):

1.5in 1.25in 1in .75in These are close measurements @welshfella

OpenStudy (18jonea):

@welshfella

OpenStudy (18jonea):

@phi

OpenStudy (phi):

divide the first number by the number after it. do that for each "pair" first/second ; second/third, third/ fourth what do you get ?

OpenStudy (18jonea):

1.2

OpenStudy (18jonea):

1.25

OpenStudy (18jonea):

1.3 repeating

OpenStudy (18jonea):

@phi @welshfella

OpenStudy (welshfella):

thats not helping looks like an arithmetic sequence as they are getting smaller by 0.25 each time

OpenStudy (phi):

I'm thinking you should get the same number. Maybe your measurements are bit off.

OpenStudy (18jonea):

Ok i thought it just is .25 adding on

OpenStudy (phi):

Oh, wait. I meant subtract each pair! what do you get ?

OpenStudy (18jonea):

.25

OpenStudy (phi):

for each pair. that is good. the formula would be a(n) = 1.5 - 0.25(n-1)

OpenStudy (18jonea):

Ok now I have to do question four

OpenStudy (18jonea):

right?

OpenStudy (phi):

yes, but means drawing four lines.

OpenStudy (18jonea):

i thought it was a figure so i was just gonna do flowers would that be ok?

OpenStudy (18jonea):

@phi

OpenStudy (phi):

yes, try it.

OpenStudy (18jonea):

OpenStudy (18jonea):

@phi

OpenStudy (18jonea):

@skullpatrol

OpenStudy (18jonea):

now i have to do numbers 5 and 6

OpenStudy (18jonea):

@agent0smith

OpenStudy (18jonea):

5 would just be the lengths right?

OpenStudy (18jonea):

@ganeshie8

OpenStudy (18jonea):

I know that a1 is 2 in and the common difference is .5 in

OpenStudy (18jonea):

@ijlal

OpenStudy (18jonea):

I just need to do the formula

OpenStudy (18jonea):

@sleepyjess

OpenStudy (18jonea):

Does anyone know

OpenStudy (18jonea):

@FibonacciChick666

OpenStudy (18jonea):

@Mehek14

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