Mathematics
21 Online
OpenStudy (18jonea):
Help please
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OpenStudy (18jonea):
OpenStudy (18jonea):
@welshfella
OpenStudy (18jonea):
@mathmale
OpenStudy (welshfella):
have you measured the lengths?
OpenStudy (18jonea):
1.5in
1.25in
1in
.75in
These are close measurements @welshfella
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OpenStudy (18jonea):
@welshfella
OpenStudy (18jonea):
@phi
OpenStudy (phi):
divide the first number by the number after it.
do that for each "pair" first/second ; second/third, third/ fourth
what do you get ?
OpenStudy (18jonea):
1.2
OpenStudy (18jonea):
1.25
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OpenStudy (18jonea):
1.3 repeating
OpenStudy (18jonea):
@phi @welshfella
OpenStudy (welshfella):
thats not helping
looks like an arithmetic sequence as they are getting smaller by 0.25 each time
OpenStudy (phi):
I'm thinking you should get the same number. Maybe your measurements are bit off.
OpenStudy (18jonea):
Ok i thought it just is .25 adding on
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OpenStudy (phi):
Oh, wait. I meant subtract each pair!
what do you get ?
OpenStudy (18jonea):
.25
OpenStudy (phi):
for each pair. that is good.
the formula would be
a(n) = 1.5 - 0.25(n-1)
OpenStudy (18jonea):
Ok now I have to do question four
OpenStudy (18jonea):
right?
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OpenStudy (phi):
yes, but means drawing four lines.
OpenStudy (18jonea):
i thought it was a figure so i was just gonna do flowers would that be ok?
OpenStudy (18jonea):
@phi
OpenStudy (phi):
yes, try it.
OpenStudy (18jonea):
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OpenStudy (18jonea):
@phi
OpenStudy (18jonea):
@skullpatrol
OpenStudy (18jonea):
now i have to do numbers 5 and 6
OpenStudy (18jonea):
@agent0smith
OpenStudy (18jonea):
5 would just be the lengths right?
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OpenStudy (18jonea):
@ganeshie8
OpenStudy (18jonea):
I know that a1 is 2 in
and the common difference is .5 in
OpenStudy (18jonea):
@ijlal
OpenStudy (18jonea):
I just need to do the formula
OpenStudy (18jonea):
@sleepyjess
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OpenStudy (18jonea):
Does anyone know
OpenStudy (18jonea):
@FibonacciChick666
OpenStudy (18jonea):
@Mehek14