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Mathematics 14 Online
OpenStudy (chris215):

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OpenStudy (chris215):

Volume = (1/2) (4/3) pi r^3

OpenStudy (ijlal):

x^2+y^2=r^2 and r=4 so i guess V=(1/2)(4/3)pi(4)^3

OpenStudy (ijlal):

not sure though ! but i guess the radius would be 4 since x^2+y^2=r^2 where r is the radius

OpenStudy (chris215):

thats wht i thought

OpenStudy (chris215):

(2/3) pi (4^3)

OpenStudy (chris215):

128pi/3 .. but i think its wrong bc it's not answer choice

OpenStudy (irishboy123):

is that on list?

OpenStudy (ijlal):

Can you mention the answer choices ? @chris215

OpenStudy (irishboy123):

because it should look like this https://gyazo.com/4d25fb1db8e63c5db1fb109c30714c44

OpenStudy (chris215):

256/3 1024π 16/3 1024/3

OpenStudy (chris215):

@IrishBoy123 it's not :/

OpenStudy (ijlal):

@IrishBoy123 is correct he gave the answer 1024/3 and its the 4th choice you mentioned

OpenStudy (ijlal):

@chris215 check again he is correct his answer is your 4th choice !

OpenStudy (irishboy123):

tx @ijlal here, you can build a new function \(A(y)\) which gives the x-sect area of the solid at any point on the y axis. So, as the x-sect at a given y is square: \(A(y) = l*l = 2 \sqrt{16- y^2} * 2 \sqrt{16- y^2} = 4 (16 - y^2)\) hence the integral in the MW link

OpenStudy (ijlal):

@IrishBoy123 can i ask a thing why couldn't we got with this? \[v=\pi \int\limits_{-4}^{4}x^2 dy \]

OpenStudy (ijlal):

|dw:1461360522428:dw|

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