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Mathematics 57 Online
OpenStudy (pphalke):

I really need help and I am willing to fan and medal

OpenStudy (pphalke):

OpenStudy (pphalke):

@mathmale

OpenStudy (pphalke):

@HyperPiper

OpenStudy (mathmale):

So: 2y = -1. Can you solve that for y?

OpenStudy (pphalke):

do I put in 0 in place of y?

OpenStudy (mathmale):

No. 2y = -1 is an equation in y. I'm asking you to solve this equation for y. Isolate y. You can do this by dividing both sides of this equation by 2. Pls show your results.

OpenStudy (pphalke):

-1/2 is that right?

OpenStudy (mathmale):

Yes, that's right. Write that as \[y=-\frac{ 1 }{ 2 }.\]

OpenStudy (mathmale):

Translate this equation into words. What does it mean in terms of graphing this function?

OpenStudy (pphalke):

I don't know

OpenStudy (mathmale):

"y=-1/2" reads "y has the constant value -1/2, regardless of the x-value." Could you visualize or actually draw a graph that suits this statement?

OpenStudy (pphalke):

no idea how I even tried desmos.com

OpenStudy (pphalke):

@563blackghost @mathmale

OpenStudy (mathmale):

" y = -1/2 " translates to: "the y-coordinate of any point of a graph is y=-1/2, regardless of x-value." (0,-1/2) is an example; (97,-1/2) is another. My point is that x can take on any value, but y always has the value -1/2. Could you graph (0, -1/2)? Start at the origin, (0,0), and move down to y=-1/2. Place a black dot there.

OpenStudy (mathmale):

@pphalke: if you want serious and prompt help, it'd be wise to stick with this discussion. There hasn't been any post by you for almost 15 minutes now.

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