Question

PLSSS HELP!!!! MEDALS!!!!


Find all solutions to the following question.
x^2-5x-6 / x+2

Answer 1

Your problem is this right?

\[\Large \frac{x^2-5x-6}{x+2}\]

or is it something else?

Answer 2

Yes it is like that

Answer 3

ok so you'll factor the numerator. Think of 2 numbers that

a) multiply to -6 (last term)
AND
b) add to -5 (middle coefficient)

what two numbers meet the conditions above?

Answer 4

(x-6)(x+1)

Answer 5

very nice

Answer 6

ok so we now have
\[\Large \frac{(x-6)(x+1)}{x+2}\]

Answer 7

nothing will cancel since we don't have any common factors

Answer 8

is the original expression in your problem set equal to anything? like equal to 0?

Answer 9

yeah equal to zero

Answer 10

so the problem is really this?
\[\Large \frac{x^2-5x-6}{x+2}=0\]

Answer 11

yes

Answer 12

ok awesome

Answer 13

the denominator will NEVER be equal to zero. You cannot divide by zero

Answer 14

So if the fraction equals zero, then only the numerator can be zero

Answer 15

that means if
\[\Large \frac{x^2-5x-6}{x+2}=0\]
then
\[\Large x^2-5x-6=0\]
agreed?

Answer 16

agreed.

Answer 17

recall that you factored x^2-5x-6 to get (x-6)(x+1)

Answer 18

So
\[\Large x^2-5x-6=0\]
turns into
\[\Large (x-6)(x+1)=0\]

Answer 19

yes so then the zeros would be -1 and 6

Answer 20

from here you use the zero product property

Answer 21

`yes so then the zeros would be -1 and 6`
very nice

Answer 22

those are your two results

Answer 23

Ok thank you!!!!

Answer 24

no problem