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Mathematics 7 Online
OpenStudy (cbreadbox):

This problem is a bit vague and I need help. http://imgur.com/hBidGqI I did the first bit, and i'm working on the rest now. I just need to be sure.

zepdrix (zepdrix):

Theoretically means to ignore any weird restrictions that might be applied to phone numbers. Like for example, in the real world, at least in the United States, you can't have a phone number beginning with 911 or 555. But we ignore all of that for this problem. So let's take some random area code, maybe 817. How many possibilities for the 7 digits that follow? Well... 10 possible numbers can go in the first slot, Numbers can certainly repeat in a phone number, so we have 10 possible numbers available to the second slot. Do you see a pattern here? :)

OpenStudy (cbreadbox):

so 10^7?

jimthompson5910 (jim_thompson5910):

yes 10^7 is correct @cbreadbox

zepdrix (zepdrix):

If I'm understanding this correctly, it seems like for part c, they just want you to multiply your result from b by 301. 301 area codes were being used, so you have 301x10^7 possible phone numbers (including area codes).

OpenStudy (cbreadbox):

That makes sense now. I understand the rest of the problems.

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