Prove or Disprove: −N := {z ∈Z : −z ∈N} has the Upper Well Ordering Property.
A set of numbers has the Upper Well Ordering Property if and only if every non empty subset has a greatest element.
i know that N has a least element
i think is wrong because N is infinite so doesn't have a greatest element. is that right?
I would say yes because you are dealing with the negative numbers not the naturals. Clearly all negative numbers are bouded above by 0 and the situation is analogous to natural numbers bounded below by 0 (or 1 depending on definition).
i see your point!
It does have the upper well ordering property. Let \( A \subset -N\). Then consider \(-A=\{-a:a \in A\} \). By the (lower?) well ordering property of N, -A has a least element, and so the negative of that least element is the greatest element of A. As A is arbitary, any subset of -N has a greatest element and so -N has the upper well ordering property
i'm a little confuse!
it has upper well ordering property or not? because you said in the beginning no and in the end yes!
Umm, i said it does have the upper well ordering property in the beginning and at the end.
thanks
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