i need assistance on this
question below will fan and medal for the help
@Scooby6363 @ace-n-it @math&ing001
First find the slope using: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]Then your equation will be \(y-y_1=m(x-x_1)\)
\( (x_1,y_1) \) and \((x_2,y_2)\) are two points from your graph.
You're fortunate because those two points are clearly marked, and thus you don't have to obtain the slope from the graph itself (without points marked).
115-147 _________ 50-10
is this supposed to look this way
Yep, exactly like that, then simplify
-32/40?
-32/40 = -4/5
how do i make the equation
Just like I aid before \( y-y_1=m(x-x_1) \) Plug in m, the slope, and a point (x1,y1) from the graph.
Even if you do it only in your mind, label the slope "m." m=-4/5 which one of the equations of a straight line, that you and I used before, will you now use? Keep in mind that you have the slope and one point on the line.
math&ing001's equation is just fine for this purpose. It's called the "point-slope" formula for the equation of a straight line.
@math&ing001 y-147=m(x-10)
Aren't you going to put in the value of the slope, m?
its asking an equation of the line and isnt the slope m=-4/5? it isnt asking to graph
Yes but you still need to plug in the slop in the equation, even if you're not going to graph it. Here y-147=m(x-10), you just replace m with its value -4/5
You want the specific equation of this line. You have y-147=m(x-10). As math&ing001 has said, simply plug in "-4/5" for m. Write out your result, please.
is it supposed to be y-147=-4/5-10?
Yes, almost, but you must include the "x" in there. Remember, x and y are the variables in any equation of a straight line that is neither vertical nor horiz. Please copy your previous equation and fix it as follows: 1) include the variable 'x' and 2) enclose the -4/5 within parentheses.
how do i do that?
@math&ing001
have you understood the question @math&ing001 and @mathmale
It's just a problem with folding : y-147=m(x-10) turs into \(y-147=-\frac{4}{5}(x-10) \) If you fold it, it's \(y-147=-\frac{4}{5}x-8 \)
MATH&ING001'S presentation is the most elegant in that he / she has correctly expressed that slope as -4 ---- 5 ...which eliminates the need for parentheses. If you don't want to go thru the trouble of using fancy graphics, then write (-4/5)x.
how do i turn that into an equation of the line as it states?
Have you any doubts that math& and I have understood the original question? if so, please explain.
It's already the equation of a line. What you have now is, as I said before, in point-slope form. That equation could be simplified a bit, but unless y ou MUST present the equation in point-slope form, you're done solving the problem.
\[y-147=-\frac{4}{5}x-8\] is the equation of the line that you were supposed to find. If you'd like to simplify it, multiply all four terms by the LCD, which is 8.
it says to simply my answer and type it in slope-intercept form
**simplify and type it in slope intercept form
@math&ing001 and @mathmale
You now have \[y-147=-\frac{4}{5}x-8\] Only one of these terms is a fraction. That fractional term has the denom. 5. Multiply all 3 terms by 5 and present below what you get.
Earlier I said the LCD is 8; that was wrong. The LCD is 5. In other words, the only term that is a fraction is 4/5; multiplying all four terms by 5 will remove the fraction.
Puting in slope intercept form, is just like solving for y. Can you solve here for y ?\[ y-147=-\frac{4}{5}x-8 \]
math^ing001: You are, of course, right on track. But why present an alternative approach when another (mine) is right on the table and eliminates struggling with fractions?
y =mx+b ---> slope intercept form
Given:\[y-147=-\frac{4}{5}x-8\] ... multiply all four terms by 5. Result begins with 5y. Can you finish this? \[5(y-147=-\frac{4}{5}x-8)=?\]
This time it is I who needs to leave. I'll be back later, just in case this problem still needs finishing then.
@mathmale it's because she doesn't need to get rid of the fraction, it's alright if the slope is like that. She could just add 147 on both sides to get the final form : \[ y-147=-\frac{4}{5}x-8 \]\[ y=-\frac{4}{5}x+139 \]
sorry i was having dinner its actually y=-0.8x+155 @math&ing001
how do i find the rate of change in the target heart rate
@Scooby6363 @math&ing001 @Mehek14
Yeah I made a mistake when folding it's \[y-147=-\frac{4}{5}x+8 => y=-\frac{4}{5}x+155\]The rate of change is = to the slope.
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